Mu-Tien, Lee
#install.packages("")
library(knitr)
library(rmarkdown)
library(MuMIn)
library(tidyverse)
library(caret)
library(corrplot)
library(readxl)
library(caret)
library(ggiraphExtra)
library(knitr)
library(ggplot2)
library(ggpubr)
library(rpart.plot)
library(rpart)
library(DT)
#read in hour data
HourData <- read.csv("hour.csv")
HourData<- HourData %>% select(-casual, -registered)
HourData$yr <- as.factor(HourData$yr)
HourData$holiday <- as.factor(HourData$holiday)
HourData$workingday <- as.factor(HourData$workingday)
#filter data by weekday
HourData <-HourData %>% filter(weekday==params$w)
#showing data
HourData <-HourData %>% select(-weekday, -workingday,-instant)
tbl_df(HourData)
## # A tibble: 2,453 x 12
## dteday season yr mnth hr holiday weathersit temp atemp hum
## <chr> <int> <fct> <int> <int> <fct> <int> <dbl> <dbl> <dbl>
## 1 2011-~ 1 0 1 0 0 1 0.16 0.182 0.55
## 2 2011-~ 1 0 1 1 0 1 0.16 0.182 0.59
## 3 2011-~ 1 0 1 2 0 1 0.14 0.152 0.63
## 4 2011-~ 1 0 1 4 0 1 0.14 0.182 0.63
## 5 2011-~ 1 0 1 5 0 1 0.12 0.152 0.68
## 6 2011-~ 1 0 1 6 0 1 0.12 0.152 0.74
## 7 2011-~ 1 0 1 7 0 1 0.12 0.152 0.74
## 8 2011-~ 1 0 1 8 0 1 0.14 0.152 0.69
## 9 2011-~ 1 0 1 9 0 1 0.16 0.152 0.64
## 10 2011-~ 1 0 1 10 0 2 0.16 0.136 0.69
## # ... with 2,443 more rows, and 2 more variables: windspeed <dbl>, cnt <int>
#Separate dataset into train (70%) and test (30%) data set
set.seed(1997)
train <- sample(1:nrow(HourData), size = nrow(HourData)*0.7)
test <- dplyr::setdiff(1:nrow(HourData), train)
HourDataTrain <- HourData[train, ]
HourDataTest <- HourData[test, ]
Here I will show you some summary of my training dataset.
1. I conduct a histogram of the rental count, since this is my response
variable.
2. I built up a summary table of all the weather measurement.
3. I also showing the weather summary via a boxplot.
4. I plot the rental count distributed by time.
5. I plot the rental count distributed by weather situation.
# plot the histogram of rental count
hist <- ggplot(data=HourDataTrain, aes(x=cnt))+geom_histogram(binwidth = 20, aes(color=yr))
hist <-hist+labs(title="Histogram of the retal count", x="rental count")
hist <-hist+scale_fill_discrete(labels=c(2011,2012))
hist
#prin out summary table for tempature humidity and windspeed
sum <- HourDataTrain%>% select(c(temp, atemp, hum, windspeed))
kable(apply(sum, 2,summary), caption="Numeric Summary for weather measurement")
temp | atemp | hum | windspeed | |
---|---|---|---|---|
Min. | 0.1000000 | 0.0909000 | 0.1600000 | 0.0000000 |
1st Qu. | 0.3600000 | 0.3485000 | 0.4900000 | 0.1045000 |
Median | 0.5200000 | 0.5000000 | 0.6600000 | 0.1940000 |
Mean | 0.5076179 | 0.4861924 | 0.6405649 | 0.1928702 |
3rd Qu. | 0.6600000 | 0.6212000 | 0.8100000 | 0.2836000 |
Max. | 0.9400000 | 0.8485000 | 1.0000000 | 0.7761000 |
Numeric Summary for weather measurement
#plot the boxplot of tempature humidity and windspeed (not genralized amount)
#plot base
boxplot <- ggplot(data = HourDataTrain, aes(x=season))
#adding 4 variables
tem <-boxplot+geom_boxplot(aes(y=temp*41, group=season))+labs(y="Tempature (c)", title = "boxplot for weather measurement")
fetem <-boxplot+geom_boxplot(aes(y=atemp*50, group=season))+labs(y="Feeling Tempature (c)")
hum <-boxplot+geom_boxplot(aes(y=hum*100, group=season))+labs(y="Humidity")
wind <-boxplot+geom_boxplot(aes(y=windspeed*67, group=season))+labs(y="Wind Speed")
#combine 4 plots into 1
ggarrange(tem, fetem, hum , wind, ncol = 2, nrow = 2)
# plot the count distribution among time and weather
# by time
barplot1<-ggplot(data = HourDataTrain, aes(x=hr))+geom_col(aes(y=cnt, fill=yr))+facet_wrap(~mnth)
barplot1 <- barplot1+labs(x="time", y="Rental Count", title="Retal count distribution by month" )
barplot1+scale_fill_discrete(name="year", labels=c(2011,2012))
# by weather
barplot2 <-ggplot(data = HourDataTrain, aes(x=weathersit))+geom_col(aes(y=cnt, fill=yr))+facet_wrap(~mnth)
barplot2 <- barplot2+labs(x="Weather situation, 1: clear day, 2: misty day, 3:rain or snow", y="Rental Count", title="Retal count distribution by month" )
barplot2+scale_fill_discrete(name="year", labels=c(2011,2012))
Here I use two different method to train my model. First method is using
a tree-based models with leave one out cross validation. For the second
method, I use the boosted tree model with cross validation. Both two
training are done using the train
function from caret
package. The
data was cantered and scaled before training.
Since our respons variable is continuous. I use the regression tree
model to training my data. The method= "rpart"
was used in train
function
Moreover, because I want to use the leave-one-out cross validation for
this training, therefore,the method= "LOOCV"
was used in
trainControl
.
We can adjust the grid parameter by ourselves. Since the default result
shows that cp
should be very small to have a lowest RMSE. I set a
range [0.0001,0.0005] to fit for every weekday.
Something to notice, because the cp
is too small, when I draw my
regression tree, it seems like a mess.
# set up training control, using leave one out cross validation.
set.seed(615)
trctrl <- trainControl(method = "LOOCV", number = 1)
# getModelInfo("rpart")
# training using regression tree models with cp in [0.0001,0.0005]
# since the cp seems have to be really small when I used the default cp to train
model1 <- cnt~season+yr+mnth+hr+holiday+weathersit+temp+atemp+hum+windspeed
RegTree_fit1 <- train(model1, data = HourDataTrain, method = "rpart",
trControl=trctrl,
preProcess = c("center", "scale"),
tuneGrid=expand.grid(cp=seq(0.0001,0.0005,0.00004))
)
# show the training result
RegTree_fit1
## CART
##
## 1717 samples
## 10 predictor
##
## Pre-processing: centered (10), scaled (10)
## Resampling: Leave-One-Out Cross-Validation
## Summary of sample sizes: 1716, 1716, 1716, 1716, 1716, 1716, ...
## Resampling results across tuning parameters:
##
## cp RMSE Rsquared MAE
## 0.00010 64.74131 0.8810503 37.57114
## 0.00014 64.74553 0.8810451 37.52645
## 0.00018 64.78678 0.8808487 37.58862
## 0.00022 64.72886 0.8810907 37.55060
## 0.00026 64.72868 0.8810750 37.36727
## 0.00030 65.06455 0.8798016 38.51957
## 0.00034 65.07244 0.8797776 38.56849
## 0.00038 65.48247 0.8782669 39.24470
## 0.00042 65.71466 0.8774079 39.52932
## 0.00046 66.03233 0.8762008 40.11507
## 0.00050 66.00767 0.8762390 40.08113
##
## RMSE was used to select the optimal model using the smallest value.
## The final value used for the model was cp = 0.00026.
# plot the RMSE of selected cp
plot(RegTree_fit1)
# plot my final tree model
rpart.plot(RegTree_fit1$finalModel)
Here I want to training my data using boosted tree model. The method=
"gbm"
was used in train
function
Because I want to use thecross validation for this training,
therefore,the method= "cv"
was used in trainControl
.
We can adjust the grid parameter by ourselves. I set a range of number
of tree [100,1250] and interaction 5~11 to fit for every weekday.
# set up training control, using cross validation with 10 folder
set.seed(615)
trctrl <- trainControl(method = "cv", number = 10)
# training using boosted tree models with boosting interation in [700,1250] and try max tree depth 5~9
model2 <- cnt~season+yr+mnth+hr+holiday+weathersit+temp+atemp+hum+windspeed
RegTree_fit2 <- train(model2, data = HourDataTrain, method = "gbm",
trControl=trctrl,
preProcess = c("center", "scale"),
tuneGrid=expand.grid(n.trees=seq(100,1250,25),
interaction.depth=5:11,
shrinkage=0.1, n.minobsinnode=10)
)
# show the training result of boosted tree
RegTree_fit2$bestTune
## n.trees interaction.depth shrinkage n.minobsinnode
## 148 250 8 0.1 10
# plot the RMSE of different parameters
plot(RegTree_fit2)
Using the best boosted tree model to testing the data.
# predict use predict function
tree_pred <- predict(RegTree_fit1, newdata = HourDataTest)
#Calculate the Root MSE
RMSE_tree<- sqrt(mean((tree_pred-HourDataTest$cnt)^2))
label <- paste0("RMSE =", RMSE_tree)
# plot the prediction
count <- data.frame(true_count=HourDataTest$cnt,prediction=tree_pred )
predPlot <- ggplot(data=count, aes(x=true_count,y=prediction))
predPlot <- predPlot+labs(title="Prediction V.s. True Count using tree-base model")+geom_point()
predPlot <- predPlot+geom_smooth(color="orange")+geom_abline(aes(intercept=0,slope=1), color="blue")
predPlot <- predPlot+geom_text(x=200, y=600,label=label, color="brown")
predPlot
# predict use predict function
boosted_pred <- predict(RegTree_fit2, newdata = HourDataTest)
#Calculate the Root MSE
RMSE_boosted <- sqrt(mean((boosted_pred-HourDataTest$cnt)^2))
lab <- paste0("RMSE =", RMSE_boosted)
# plot the prediction
count2 <- data.frame(True_count=HourDataTest$cnt,prediction=boosted_pred )
pred_plot <- ggplot(data=count2, aes(x=True_count,y=prediction))
pred_plot <- pred_plot+labs(title="Prediction V.s. True Count using boosted model")+geom_point()
pred_plot <- pred_plot+geom_smooth(color="orange")+geom_abline(aes(intercept=0,slope=1), color="blue")
pred_plot <- pred_plot+geom_text(x=200, y=600,label=lab, color=" brown")
pred_plot
# create a linear model using repeated cross-validation
linear_mod <- train(cnt~season+yr+mnth+hr+holiday+weathersit+temp+atemp+hum+windspeed,
data=HourDataTrain,
method='lm',
preProcess=c("center", "scale"),
metric='RMSE',
tuneLength=10,
trControl=trainControl(method='repeatedcv', number=10, repeats=3)
)
# display the results of the linear model
summary(linear_mod)
##
## Call:
## lm(formula = .outcome ~ ., data = dat)
##
## Residuals:
## Min 1Q Median 3Q Max
## -340.76 -95.32 -37.89 47.51 614.28
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 189.768 3.640 52.139 < 2e-16 ***
## season 18.301 9.300 1.968 0.0492 *
## yr1 42.602 3.680 11.578 < 2e-16 ***
## mnth 7.519 9.291 0.809 0.4185
## hr 60.898 3.828 15.909 < 2e-16 ***
## holiday1 -10.653 4.450 -2.394 0.0168 *
## weathersit -7.395 4.254 -1.738 0.0824 .
## temp -33.530 31.286 -1.072 0.2840
## atemp 76.435 31.279 2.444 0.0146 *
## hum -33.906 4.643 -7.302 4.33e-13 ***
## windspeed 8.173 3.972 2.058 0.0398 *
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 150.8 on 1706 degrees of freedom
## Multiple R-squared: 0.3541, Adjusted R-squared: 0.3503
## F-statistic: 93.52 on 10 and 1706 DF, p-value: < 2.2e-16
# compare our linear model to our test data
linear_pred <- predict(linear_mod, newdata=HourDataTest)
postResample(linear_pred, HourDataTest$cnt)
## RMSE Rsquared MAE
## 155.1096182 0.3296524 115.1139742